To complete and balance the equation for the reaction of nitrogen dioxide (NO₂), oxygen (O₂), and water (H₂O) above 200°C, we follow these steps:
Step 1: Write the unbalanced equation
The unbalanced equation based on the reactants provided is:
NO2+O2+H2O→?
Step 2: Identify the product
When NO₂ reacts with O₂ and H₂O at elevated temperatures, it forms nitric acid (HNO₃). Thus, we can write:
NO2+O2+H2O→HNO3
Step 3: Write the initial equation with the product
Now we can express the reaction with the product:
NO2+O2+H2O→HNO3
Step 4: Balance the equation
1. Count the number of each atom on both sides:
- Reactants:
- N: 1 (from NO₂)
- O: 2 (from NO₂) + 2 (from O₂) + 1 (from H₂O) = 5
- H: 2 (from H₂O)
- Products:
- N: 1 (from HNO₃)
- O: 3 (from HNO₃)
- H: 1 (from HNO₃)
2. Balance the hydrogen atoms:
To balance the hydrogen atoms, we need 2 HNO₃:
NO2+O2+H2O→2HNO3
3. Update the count:
- Reactants:
- N: 1
- O: 5
- H: 2
- Products:
- N: 2 (from 2 HNO₃)
- O: 6 (from 2 HNO₃)
- H: 2 (from 2 HNO₃)
4. Balance the nitrogen:
We need 2 NO₂ to tát balance the nitrogen:
2NO2+O2+H2O→2HNO3
5. Update the count again:
- Reactants:
- N: 2
- O: 4 (from 2 NO₂) + 2 (from O₂) + 1 (from H₂O) = 7
- H: 2
- Products:
- N: 2
- O: 6 (from 2 HNO₃)
- H: 2
6. Balance the oxygen:
To balance oxygen, we need to tát adjust the number of O₂ and H₂O. We can use 2 H₂O:
2NO2+1O2+2H2O→2HNO3
7. Final check:
- Reactants:
- N: 2
- O: 4 (from 2 NO₂) + 2 (from O₂) + 2 (from 2 H₂O) = 8
- H: 4 (from 2 H₂O)
- Products:
- N: 2
- O: 6 (from 2 HNO₃)
- H: 4
Final Balanced Equation
The balanced equation is:
4NO2+O2+2H2O→4HNO3
The unbalanced equation based on the reactants provided is:
NO2+O2+H2O→?
When NO₂ reacts with O₂ and H₂O at elevated temperatures, it forms nitric acid (HNO₃). Thus, we can write:
NO2+O2+H2O→HNO3
Now we can express the reaction with the product:
NO2+O2+H2O→HNO3
1. Count the number of each atom on both sides:
- Reactants:
- N: 1 (from NO₂)
- O: 2 (from NO₂) + 2 (from O₂) + 1 (from H₂O) = 5
- H: 2 (from H₂O)
- Products:
- N: 1 (from HNO₃)
- O: 3 (from HNO₃)
- H: 1 (from HNO₃)
To balance the hydrogen atoms, we need 2 HNO₃:
NO2+O2+H2O→2HNO3
- Reactants:
- N: 1
- O: 5
- H: 2
- Products:
- N: 2 (from 2 HNO₃)
- O: 6 (from 2 HNO₃)
- H: 2 (from 2 HNO₃)
We need 2 NO₂ to tát balance the nitrogen:
2NO2+O2+H2O→2HNO3
- Reactants:
- N: 2
- O: 4 (from 2 NO₂) + 2 (from O₂) + 1 (from H₂O) = 7
- H: 2
- Products:
- N: 2
- O: 6 (from 2 HNO₃)
- H: 2
To balance oxygen, we need to tát adjust the number of O₂ and H₂O. We can use 2 H₂O:
2NO2+1O2+2H2O→2HNO3
- Reactants:
- N: 2
- O: 4 (from 2 NO₂) + 2 (from O₂) + 2 (from 2 H₂O) = 8
- H: 4 (from 2 H₂O)
- Products:
- N: 2
- O: 6 (from 2 HNO₃)
- H: 4
The balanced equation is:
4NO2+O2+2H2O→4HNO3